SHORT CIRCUIT CALCULATIONS
|Symmetrical components||Power invariance||Impedance transformation||Sequence networks|
|Fault analysis||Causes of system faults||Symmetrical faults||Sudden 3-ph short-circuit of unloaded generator-Definition of reactances|
|System representation during short circuit||Thevenin's equivalent||Three-phase fault||Single-line to ground fault|
|OBJECTIVE TYPE QUESTIONS|
Internet sites:ABC012: Handy phase sequence calculator. Microsoft Fortran Power Station 4.0 source and executable are included. http://www.ece.utexas.edu/~grady/PCFLO.html ( contains PCFLOW - short circuit, load flow and harmonics program)
SHORT-CIRCUIT ANALYSIS -OBJECTIVE TYPE QUESTIONS
(a) Zs = 0.7 pu, Zm =0.2 pu
(b) Zs = 0.5 pu, Zm =0.6 pu
(c)Zs = 1 pu, Zm =0.6 pu
(a) the positive and negative sequence networks at the fault point are
connected in series
(b) the positive and negative sequence networks at the fault point are
connected in parallel
(c) the positive, negative, and zero sequence networks at the fault point are
connected in parallel
The correct alternative is
These were developed to ease the calculations for unbalanced 3-phase systems and as a help to numerical solution using network analyzers. Even with present day digital computation, the symmetrical components help in solution of unbalanced systems, besides explaining many phenomena such as rotor heating in machines, neutral current etc.
The basic concept is to convert a set of three phasors into another set of three phasors with certain desirable properties. The symmetrical components (introduced by Fortescue) is only one such set, the other set is the Kimbark/Clarke components.
The unique property of symmetrical components is that they retain the concept of 3-phase system associated with each component phasor. Thus the positive sequence retains the concept of 3 balanced phasors having the same phase sequence as the original phasors whereas the negative sequence component retains the concept of 3 balanced phasors but rotating in opposite direction of rotation. The zero sequence component is balanced set of 3- coincident phasors but rotating in the same direction as the original unbalanced phasors.
The basic definition for a set of unbalanced three-phase system in terms of the sequence components is
Ia = I0a + I1a +I2a
Ib = I0b + I1b + I2b + I0 a + a2 I1 a +a I2 a
Ic = I0 c +I1 c +I2 c = I0 a + a I1 a + a 2 I2 a
These equations may be written in matrix form as
I a,b,c = [Ts] I 0,1,2
Where Ts is called the symmetrical component transformation matrix.
I 0,1,2 = [Ts]-1 I a,b,c
Similar transformation may be applied for unbalanced voltages also.
Illustrate these transformations by phasor additions.
If the above transformation Ts is used simultaneously on the voltage and current values of three phase network elements, then
Spq abc = P pq + j Qpq =[( I pq abc )*]t e pq abc
Spq012 = [( I pq012)*]t e pq012
Note that Spqabc is not equal to Spq012.
Spqabc = 3Spq012 since Spq012 refers to only phase "a" power , and similar amount of power is in phases "b" and "c" also. Thus all three phases of symmetrical components must be used. Often for computer work, the symmetrical transformation given by
Tsi = (1/Ö 3) Ts
is use where Tsi*t . Tsi = unity matrix. This is a property of orthogonal matrices. Further since Tsi* = Tsi-1 we can show that Spqabc = Spq012. However, in earlier works, and even now, the originally defined non-power invariant transformation is being used
To solve the network in terms of the sequence components, sequence components of impedance are required. These are obtained from their corresponding three phase values.
Eabc = Zabc I abc
Ts E012 = Z abc Ts I 012
E012 = Tsi-1 Z abc Ts I 012
= Z012 I 012
Thus Z012 = Ts-1 Z abc Ts
Zabc = Ts Z 012 Ts-1
Forms of Z012 for balanced stationary and rotating elements should be known. Decoupling of sequence components and its limitations are to be stressed.
Sequence generated voltages in a balanced network are:
E1 = Ea, E2 = 0 , E0 =0
Sequence networks have the advantage since for balanced network there is no mutual coupling between sequence component elements unlike what happens in balanced 3-phase components. Thus balanced 3-phase network can be assembled component for component in three separate sequence networks. Sequence networks of generator, transmission line, transformer, and loads should be known. Zero sequence networks for different transformer connections should also be known. The ideal earth and the neutral point should be distinguished. Relative magnitudes of sequence impedances of generator and transmission lines should be known.
An essential part of the design of a power system is the calculation of currents which flow in the components and the resulting voltages , when the faults of various type occur. Common faults on a transmission system are;
Faults may also occur in switchgear, transformers and machines but their nature may be different than those in transmission lines.
Causes of system faults
Faults are mostly due to lightning and switching. Most of them are temporary. LG fault is most common and LLL fault is least common. Relays provided on the system detect these faults and produce a trip signal for the circuit breaker to isolate the faulty portion form the system. Thus to determine the circuit breaker and relay operating times, fault currents & voltages have to be calculated and for many other applications.
Except for the three phase faults ,all other types of faults cause unbalanced operation, an fault currents & voltages under such conditions are required to be obtained using symmetrical components, or phase components ( the latter analysis is much more difficult even with digital computers.
The calculation of 3-phase balanced faults is relatively simple but forms the basis of determining the circuit breaker ratings.
When a sudden short circuit occurs on the electric supply system, the currents & voltages are of transient nature before they settle down to steady state values.
The fault current at any time consists of
Ae-Rt/L Sin(w t + f ) where w = supply frequency
For a single machine system, the maximum value of the Dc transient could be equal to the peak value of the total Ac component.Fig.5 shows the symmetrical current in one phase with no DC offset.( Other phases will have DC offset). The cause of subtransient/transient current could be explained on the basis of the theorem of constant flux linkages associated with the field winding. The damper winding affects the initial value of the fault current. The initial value decays faster(region PQ in Fig.5) because of the very low time constant of this circuit. Later, the closed field circuit effects dominate (region QR). The region QR may be extended up to the origin as the dotted line bQ.
Definition of reactances
Xd" = Ö 2 .E. /Oa
Xd'= Ö 2 .E. /Ob
Xd= Ö 2 .E. /Oc
What are the typical values of these reactances for turbo and hydro generators?
For the interruption current rating of a circuit breaker (time involved being 2-5 cycles), the subtransient current is important. The transient current is important for transient stability studies lasting from 1-2 seconds to 10 seconds.
Short circuit volt-amperes =Ö 3. (short-circuit current). [Nominal Voltage (line value)]
System representation during short circuit
If assumptions 2-4 are not taken into account, pre-fault currents are added to the fault currents obtained by using the Thevenin's equivalent of the network.
The Thevenin's equivalent of the network at the point of the fault location (either in phase or sequence components) is obtained for calculating the fault currents. If the network is balanced before the fault, then at the fault point , Thevenin's sequence voltages become
If the network is not balanced , the above voltages may have finite values and the sequence component approach may not be useful. The performance equation for the balanced network in terms of sequence components is :
[Vs] = [Eph]- [Zs][Is],
[Eph] = [0,E1a,0]
[Zs] = diagonal matrix of [Z0,Z1,Z2]
[Is] = [I0a,I1a,I2a]
The network at the fault point F appears as shown inFig.6 where Z1,Z2 and Z0 are the lumped values of the Thevenin's impedances between the fault point and the neutral.
Depending upon the type of fault, the sequence components of currents and voltages are constrained leading to particular connections of sequence network. After the fault currents coming out of the network at the fault point are determined, the current & voltage distributions inside the network are found out . If originally, there are load currents , these are restricted to the positive sequence network , and they are superposed on the fault currents for accurate results, but this is often not done.
Ia1 = Ea/(Z1 +ZF)
Ia2 = 0
Single-line to ground (SLG)fault
Fault is assumed in phase "a". If it is in any other phase, symmetrical shifting will be required.
The connections at the fault point are given inFIG.7 for various types of faults. The connections of the sequence networks for SLG fault are given in FIG.8 .
Study the network connections for L-L and DLG faults.